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3 years ago

What is the range of the function y= 2sinx

Mathematics

2 answers:

masha68 [24]3 years ago

8 0

<h2>Answer:</h2>

The range is (-2,2)

<h2>Step-by-step explanation:</h2>

The range of sinx is 1<inx<1 or −1<y<1

It implies,

−2<2sinx<2

This means that the range of y=2sinx is −2<y<2

The lower bound of the range for sine is found by substituting the negative magnitude of the coefficient into the equation.

y=−2

The upper bound of the range for sine is found by substituting the positive magnitude of the coefficient into the equation.

y =2 The range is −2≤y≤2.

Nana76 [90]3 years ago

4 0

<h2>Hello!</h2>

The answer is: [-2,2]

The range of a function shows where the function can exist in the y-axis.

To know the range of the function, we have to isolate x,

$y=2sinx\\\frac{y}{2}=sinx\\ Sin^{-1}(\frac{y}{2}) = x$

The only possible values that y can take go from -2 to 2. Taking values out of these values will give as result a non-real number.

Therefore,

The range of the function is [-2,2]

Have a nice day!

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3 years ago

What is the range of the function y= 2sinx​

What is the range of the function y= 2sinx