Answer:
Step-by-step explanation:
Anyone who uses Latex as well as you do, shouldn't have any trouble with this question.
4^2: 4 * 4 = 16
9^3: 9 * 9 * 9 = 729
729 + 16 = 745
Ummm I'm not sure but let me do the math and I'll tell u :)
The factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)
<h3>How to factor the expression?</h3>
The expression is given as:
m(2a+b)-n(2a+b)+2n(2a+b)
Factor out 2a + b
m(2a+b)-n(2a+b)+2n(2a+b) = (m - n + 2n)(2a + b)
Evaluate the like terms
m(2a+b)-n(2a+b)+2n(2a+b) = (m + n)(2a + b)
Hence, the factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)
Read more about factored expressions at:
brainly.com/question/723406
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Answer: Aquarius ♒️ UwU
Step-by-step explanation:My Birthday is 2/11/09
<h3>
Answer:</h3>
1/17 or 0.0588 (without replacement)
<h3>
Step-by-step explanation:</h3>
To answer this question we need to know the following about a deck of cards
- A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
- Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
- Additionally, there are 13 cards in each suit (Clubs/Spades are black, Hearts/Diamonds are red)
.
In this case, we are required to determine the probability of choosing two diamonds.
- There are 13 diamonds in the deck.
- Assuming, the cards were chosen without replacement;
P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)
P(First card is diamond) = 13/52
If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.
Therefore;
P(Second card is diamond) = 12/51
Thus;
P(Both cards are diamonds) = 13/52 × 12/51
= 156/2652
= 1/17 or 0.0588
Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.
