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olga_2 [115]
3 years ago
5

Complete ☻☺ z^2 + 9z – 90 = (z – 6)(z +■) A.) -15 B.) 15 C.) 90 D.) -9

Mathematics
2 answers:
ratelena [41]3 years ago
7 0
The answer is 15,

In problems like these, the terms that are a number without a variable on one side will always multiply to the number without a variable on the other side.
Hence, -6 times the black box = -90. Divide -90 by -6 and you get positive 15.

Plug it in to check and you get (z-6)(z+15)=(z^2+9z-90).
irina [24]3 years ago
4 0
The answer is B) 15

I hope this helps
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Write the equation of the line in slope-intercept that has passes through the points (2,-5) and (8, 13). ​
const2013 [10]

Answer:

The equation of the straight line in Slope- intercept form

 y = 3 x - 11

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given points are   (2,-5) and (8, 13)

The Slope of the line

            m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} } = \frac{13-(-5)}{8-2} = \frac{18}{6} =3

Equation of the line having slope 'm' and given point

        y - y_{1} = m (x - x_{1} )

(x₁ , y₁)   =    ( 2, -5 )  

        y - (-5) = 3 (x - 2 )

       y + 5 = 3x - 6

The equation of the straight line in slope intercept form

    y = m x + c

       y = 3 x - 6-5

       y = 3 x - 11

<u><em>Final answer:</em></u>-

The equation of the straight line in Slope- intercept form

 y = 3 x - 11

     

8 0
3 years ago
N f(x) = 2x , x=5. What is the value of the function?
wel
Plug the 5 into the x in the equation 2x. it should be 2(5) which equals 10.
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Write down two expressions for the perimeter of this shape one with brackets and one without
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Eighteen less than a number is 44. find the number
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Eighteen less than a number is 44:before you answer this question you must have to think about a equation, which makes easy for you to answer these kind of questions.

look, here the question tells us that x-18=44, so the answer will be:

 x-18=44

x=44-18
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x=26</span>
3 0
4 years ago
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How would I do question 5 I don’t understand
bazaltina [42]

Answer:

a) f(0)=4

b) f(-2)=2

c) x∈{-8,-4,4,8}

d) x∈{-9,-3,3,9}

e) x∈(-∞,-9)∪(-3,3)∪(9,∞).

f)  x∈[-9,-3]∪[3,9]

g) Domain is x∈[-10,10]. Range is y∈[-4,4]. Zeros are at elements of x in {-9,-3,3,9}

h) Increasing on x∈ (-6,0) ∪ (6,10) and

decreasing on x∈ (-10,-6) ∪ (0,6).

Step-by-step explanation:

a) f(0) means what is the y-coordinate of the point at x=0.

So find 0 on the x-axis. I'm going to go up because the curve is at y=4 there.

Conclusion: f(0)=4.

b) f(-2) means what is the y-coordinate of the point at x=-2.

So find -2 on the x-axis. I'm going to go up because the curve is at y=2 there.

Conclusion:  f(-2)=2.

c) f(x)=-2 means what is x when y=-2.  So go on the y-axis and find -2. Now anything on that line y=-2 (horizontal line going through y=-2 on the y-axis) we need to look at.

There are 4 value we need to look at then.

x=-8

x=-4

x=4

x=8

At all of these the y-coordinate is -2.

d) f(x)=0 means what is x when y=0.  So go on the y-axis and find 0. Now anything on that line y=0 (horizontal line going through y=0 on the y-axis; also knowing as the x-axis for y=0) we need to look at.

There are 4 values we need to look at then.

x=-9

x=-3

x=3

x=9

e)  f(x)>0 means where is the curve above the x-axis.

The curve is above the x-axis:

  • Before x=-9
  • Between x=-3 and x=3
  • After x=9

The interval notation is:

(-∞,-9)∪(-3,3)∪(9,∞).

d) f(x)≥0 means where is the curve below or on the x-axis (also known as y=0).

The curve is below or on the x-axis:

  • Between -9 and -3 (inclusive of both endpoints because they include y=0).
  • Between 3 and 9 (inclusive of both endpoints because they include y=0).

The interval notation is:

[-9,-3]∪[3,9]

g) The domain is where the curve exists for the x-values.

The domain is all real numbers between -10 and 10 (inclusive of both).

The curve starts at x=-10 and stops at x=10. The function exists a y value for any number between -10 and 10 (including both).

Interval notation is:

[-10,10]

The range is where the curve exists for the y-values.

Looking from bottom to top I see that it starts at y=-4 and stops at y=4. I notice the curve exists at some point between those two horizontal lines. It also exists at both of those endpoints" -4 and 4.

The range is between -4 and 4 (including both).

Interval notation is:

[-4,4]

The zeros are where the graph crosses the x-axis.

The graph crosses the x-axis at:

x=-9

x=-3

x=3

x=9

h)  Reading left to right the graph increases when you see the curve going up.

I see this from x=-6 to x=0 (exclusive of both).

I see this from x=6 to x=10 (exclusive of both).

So interval notation is (-6,0) ∪ (6,10).

Reading left to right the graph decreases when you see the curve going down.

I see this from x=-10 to x=-6 ( exclusive of both).

I see this from x=0 to x=6 (exclusive of both).

4 0
3 years ago
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