Answer: 1
Step-by-step explanation:
Please see attached
What forms do the equations of motion for an idealized string take if either (a) the linear density varies with position, or (b)
the string hangs vertically supported only at the upper end?
1 answer:
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Answer:
Step-by-step explanation:
3(2 + 4x) = -7 x 2 Distribute the 3
6 + 12x = -14 Subtract 6 from both sides of the equation
12x = -20 Divide both sides by 12
x = Divide the top and the bottom of the fraction by 4
x =
The equation of the line can be shown using the slope intercept form that is
y= mx+b
where m is the slope and b is the y intercept
So firstly we have to find the value of slope m
To find the value of slope m we apply the formula
So we can plug the values using the two given points
(-0.5,0.75) and (0.75,-0.5)
So m = -1
Plug m=-1 in the equation we get
y= -1x +b
Now we have to find the value of b
to find the value of b , we plug any one pint in the equation
0.75 = -1(-0.5) +b
0.75 = 0.5 +b
Subtract 0.5 from both sides
0.25 = b
or
b= 0.25
Now plug the value of b , in the equation
we get
y = -1x +0.25
hence the equation of the line is y = -1x +0.25