Answer:
∠ D = 28°
Step-by-step explanation:
The external angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ EBC is an exterior angle of Δ ABE, thus
∠ EBC = 90° + 34° = 124°
BD bisects ∠ EBC, so
∠ EBD = 124° ÷ 2 = 62° , then
∠ D = 180° - (90 + 62)° = 180° - 152° = 28° ( angle sum of triangle )
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Answer:
x-coordinate.
Step-by-step explanation:
its the answer for edge.
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
The answer is 101
100 squared is 10,000
Then form an equation
100u-100=10,000
+100 +100
100u=10,100
divide by 100 on both sides
and you get 101 as the answer
