3 years ago

Divide and simplify as much as possible: -20v^7 x^7 + 12v^4 x^7 / 4v^5 x^4

1 answer:

5 0

$\dfrac{-20v^7x^7+12v^4x^7}{4v^5x^4}=\dfrac{-20v^7x^7}{4v^5x^4}+\dfrac{12v^4x^7}{4v^5x^4}=-5v^{7-5}x^{7-4}+3v^{4-5}x^{7-4}\\\\=\boxed{3v^{-1}x^3-5v^2x^3}$

Used

$\dfrac{a^n}{a^m}=a^{n-m}$

Other method:

$\dfrac{-20v^7x^7+12v^4x^7}{4v^5x^4}=\dfrac{4v^4x^4(-5v^3x^3+3x^3)}{4v^4x^4(v)}=\dfrac{3x^3-5v^3x^3}{v}$

You might be interested in

The five posters made for spirit week are being hung in the front hall. What is the probability the largest poster will be in th

Leto [7]

Answer:

1/20 or 0.05

Step-by-step explanation:

Assuming that all five posters are different, the number of ways to randomly place those posters is given by:

$N=5*4*3*2*1 = 120\ ways$

If we want the largest to be in the center and the next largest to be on its left, two poster will have a set position and only three could be randomized:

$n=3*2*1*1*1=6\ ways$