All categories

3 years ago

Divide and simplify as much as possible: -20v^7 x^7 + 12v^4 x^7 / 4v^5 x^4

1 answer:

5 0

$\dfrac{-20v^7x^7+12v^4x^7}{4v^5x^4}=\dfrac{-20v^7x^7}{4v^5x^4}+\dfrac{12v^4x^7}{4v^5x^4}=-5v^{7-5}x^{7-4}+3v^{4-5}x^{7-4}\\\\=\boxed{3v^{-1}x^3-5v^2x^3}$

Used

$\dfrac{a^n}{a^m}=a^{n-m}$

Other method:

$\dfrac{-20v^7x^7+12v^4x^7}{4v^5x^4}=\dfrac{4v^4x^4(-5v^3x^3+3x^3)}{4v^4x^4(v)}=\dfrac{3x^3-5v^3x^3}{v}$

You might be interested in

A stadium has 39 sections. there are 18 sections that each have 478 seats. The remaining sections each have 292 seats. If 13,528

vesna_86 [32]

Answer: 1,208 seats

Step-by-step explanation:

39-18= 21

18 x 478 = 8,604

21 x 292 = 6,132

8,604 + 6,132 = 14,736

14,736 - 13,528 = 1,208

6 0

3 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

3 years ago

Solve by graphing.

const2013 [10]

Answer:

(4,4)

Step-by-step explanation:

y = 2x - 4 -------eqn 1

4y = x + 12 ------eqn 2

From eqn 1 y = 2x - 4; insert in eqn 2

4 (2x-4) = x + 12 (open the bracket)

8x - 16 = x + 12 (taking like figures to the same side, sign changes)

8x - x = 12 + 16

7x = 28

x = 28/7

x = 4

From eqn 1

y = 2x - 4

y = 2(4) - 4

y = 8 - 4

y = 4

(x,y) = (4,4)

8 0

3 years ago

The length of a rectangle is 8 inches more than three times the width. the perimeter is 88 inches. find the length and width.

Sav [38]

We can say L as length and W as the width

L= 3w + 8

The formula for perimeter is 2L + 2W = P. We can substitute L in as "3w+8" to make the equation...

2(3w+8)+2w=88 Now, we can simplify by distributing the 2 to each term
6w+16+2w=88
8w+16=88 Then subtract 16 from each side..
8w=72
w=9

So the width is 9, so we can substitue that into the previous equation, L = 3w+8.

L=3(9)+8
L=27+8
L=35, W=9

5 0

3 years ago

Dang this is hard quiz

olga nikolaevna [1]

Answer:

-54

Step-by-step explanation:

8 0

2 years ago