Question

What is the product of (3y^-4) (2y^-4) A. 6/y^8 B. 1/6y^8 C. 6/y^16 D. 1/6y^16

Answer 1

Answer:

A

Step-by-step explanation:

We want to simplify the product $(3y^{-4})(2y^{-4})$.

First, notice that both terms have a power with base y, so by the properties of exponents, we can combine the two $y^{-4}$ into one by adding their exponents:

$y^{-4}*y^{-4}=y^{-4+(-4)}=y^{-8}$

Now, let's multiply the 3 and 2:

3 * 2 = 6

So far, we have $6y^{-8}$. However, we have a negative exponent that we want to make positive. Remember another property of exponents that when we have a negative exponent, we can make it positive by taking the reciprocal of it. Thus, $y^{-8}$ becomes $\frac{1}{y^8}$.

Hence, our answer is $6*\frac{1}{y^8}=\frac{6}{y^8}$, or A.

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