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enot [183]
3 years ago
14

What is the solution of the equation when solved over the complex numbers?

Mathematics
1 answer:
kumpel [21]3 years ago
3 0

Answer:

x=+i\sqrt{20}\approx+4.472i

x=-i\sqrt{20}\approx-4.472i

Step-by-step explanation:

Starting from x^2+20=0, we do x^2=-20, which means x=\pm\sqrt{-20}, which can be written as x=\pm\sqrt{(-1)(20)}, which gives us x=\pm\sqrt{(-1)}\sqrt{(20)}, which we know is x=\pm i \sqrt{(20)}, so our solutions are:

x=+i\sqrt{(20)}

x=-i\sqrt{(20)}

Which can be approximated to:

x\approx+4.472i

x\approx-4.472i

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