The formula that is useful for solving both of these problems is ...

9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
Answer:
35 m/s
Step-by-step explanation:
Let gravitational acceleration g = 9.8m/s2. We can calculate the amount of time for the ball to fall vertically a distance of 1.6 m



This is also the time it takes for the ball to fly horizontally, assume constant horizontal speed, we can calculate the speed it takes to travel across 20m in 0.571s
v = 20 / 0.571 = 35 m/s
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + (x + 2) = 108...ur equation
3x + 3 = 108...ur equation that has been simplified some
Answer: 62.8 yd
Step-by-step explanation:
Circumference= diameter*pi
20*3.14= 62.8