Steve spent $24 on dog grooming supplies he washed six dogs and charge the owner $12 per dog wash how much money did steve earn

Which statement about isosceles triangles is true?

Paraphin [41]

C- I’m assuming that you meant to say that they have one angle that is equivalent to another
All isosceles triangles have two sides that are of equal length

7 0

3 years ago

(y - 2)2 = y2 – 6y + 4 Is this statement true or false?

trasher [3.6K]

<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0

2 years ago

Read 2 more answers

It takes 20 hours and $400 to interview a candidate, and it takes 120 hours and $3600 to train an employee. A company has less t

zavuch27 [327]

Let C denote the number of candidates they interview and E the number of employees they train.

If it takes 20 hours and $400 to interview a candidate, then it takes 20C hours and $400C to interview C candidates.

If it takes 120 hours and $3600 to train an employee, then it takes 120E hours and $3600E to train E employees.

Company has less than $95000, then 400C+3600E<95000.

Company wants to spend at most 470 hours, then $20C+120E\le
 470$ .

You obtain the system of two inequalities:


$\left \{ {{400C+3600E\ \textless \ 95000} \atop {20C+120E\le
 470}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {C+6E\le 
23.5}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {4C+24E\le 
94}} \right.$
Then you can solve this system according to your demands.

3 0

2 years ago

Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ

bixtya [17]

Answer:

$AB=2\sqrt{ab}$

Step-by-step explanation:

From figure,

$OA=a, \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)$

In triangle $OO'D$

$(OO')^2=(OD)^2+(O' D)^2$

$\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]$

Hence, $AB=2\sqrt{ab}$

6 0

3 years ago

The annual snowfall in city A is 58.7 inches. This is 12.5 inches more than six times the snowfall in city B. Find the annual sn

Lelechka [254]

The annual snowfall for city B is 7.7 inches.
Since it is 12.5 inches more: 58.7 - 12.5 = 46.2
Since 46.2 is 6 times that of city B: 46.2 / 6 = 7.7

3 0

2 years ago

Read 2 more answers