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Soloha48 [4]
4 years ago
7

What is the scientific notation of 0.0000855

Mathematics
2 answers:
Novay_Z [31]4 years ago
6 0
8.55 times 10 to the 5th
Schach [20]4 years ago
3 0

It would be 8.55 x  10^{-5}

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3(x-1) - 8 = 4(1+x) +5​
juin [17]

Answer:

x=-20

Step-by-step explanation:

3x-11=4x+9

3x=4x+20

x+20=0

x=-20

8 0
3 years ago
Read 2 more answers
what is the height of a trapezoid with one base equal to 20m, the other base equal to 7m, and an area of 135m^2
german

Answer:

<h2>The height is 10 m</h2>

Step-by-step explanation:

Area of a trapezoid is given by

<h3>A =  \frac{1}{2} (a + b)h</h3>

where

a and b are the bases

h is the height

From the question

A = 135 m²

a = 20m

b = 7 m

Substitute the values into the above formula and solve for the height

That's

<h3>135  = \frac{1}{2} (20 + 7)h \\ 135 =  \frac{1}{2}  \times 27h \\ 135 \times 2 =  2 \times \frac{1}{2}  \times 27h \\ 270 = 27h</h3>

<u>Divide both sides by 27</u>

That's

<h3>\frac{27h}{27}  =  \frac{270}{27}</h3>

We have the final answer as

<h3>10 m</h3>

Hope this helps you

5 0
4 years ago
Find the value of x​ . Round your answer to the nearest tenth.
Sunny_sXe [5.5K]
I think its either 9 or 10
5 0
3 years ago
Probably simple math. 20 points.
Harlamova29_29 [7]

ok well first you would find what the square root would be then you just see where it falls on the number line

so the sqrt of 29 is 5.38516... so it falls between 5 and 6.

so the answer is 5 and 6

6 0
3 years ago
Read 2 more answers
If the odd against the occurence of an event be 4:7 find the proabilty of the occurence of the event.
Alla [95]

Answer:

Probability = \frac{7}{11}

Step-by-step explanation:

Given

Odds:Occurence = 4:7

Required

Determine the probability of the occurrence

First, we need to get the total of the ratio

Total = 4 + 7

Total = 11

Next, is to calculate the required probability as follows;

Probability = \frac{Occurrence}{Total}

Probability = \frac{7}{11}

<em>Hence, the required probability is </em>

Probability = \frac{7}{11}

6 0
4 years ago
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