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iren2701 [21]
3 years ago
5

Identify p, b, and a. Do not solve for the unknown. 10.9 is what percent of 34?

Mathematics
1 answer:
Rashid [163]3 years ago
8 0
10.9 = x% of 34

10.9 is the amount
x% is the percent
34 is the base
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The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:
Marina CMI [18]
<h2>Answer:</h2>

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

                                 Origin.

<h2>Step-by-step explanation:</h2>

A function f(x) is said to be a odd function if:

                    f(-x)=-f(x)

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

                      f(-x)=f(x)

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

\tan(-x)=-\tan x\\\\\cos (-x)=-\cot x\\\\\csc (-x)=-\csc x

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

<em>Hence, the graph of tangent function, cotangent function and cosecant function  is symmetric about the origin.</em>

7 0
3 years ago
Another how many liters are in 3.7 gallons
9966 [12]
I got:
37 times 3.79 = 140.23
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Round off 0.065 to one significant figure
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I think what you are wanting id 0.1 is that rounded to one significant figure

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Find the slope and the y-intercept of the line.
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2 years ago
A study of the career paths of hotel general managers sent questionnaires to an SRS of 160 hotels belonging to major U.S. hotel
otez555 [7]

Answer:

(10.78483, 12.61517)

Step-by-step explanation:

It is given that the genera mangers of few hotels were sent some questionnaires for conducting a study for the career paths in the major hotel chains of the United States.

Number of hotels = 160

Number of response received = 103

The average number of years these general mangers was in their current hotels, $\bar x$ = 11.7 years

Confidence Interval, CI = 0.99

Therefore,

a = 0.01, |Z(0.005)|  (from standard normal table)

∴ 99% of CI =  $\bar x \pm Z \times \frac{s}{\sqrt n}$

                   $= 11.7 \pm 2.58 \times \frac{3.6}{\sqrt {103}}$

                    $(10.78483, 12.61517)$

3 0
3 years ago
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