Will give brainlist what is the approximate area of the figure

Mathematics

2 answers:

ruslelena [56]4 years ago

3 0

The radius of this circle is 4 centimeters, so the area of half of the circle will be 25.135, I'll call it 25.

The rectangle is 8 cm by 14 cm, so that has an area of 112.

Now, add 25 and 112. This will give you about 137.

almond37 [142]4 years ago

3 0

Answer:

the answer is 137.1

Step-by-step explanation:

Divide the figure into recognizable shapes. Find the area of each shape and add them together.

You might be interested in

Multiply −3x2(6x2 2x − 3). −18x2 − 6x 9 −18x4 − 6x3 9x2 3x2 − x − 6 3x4 − x3 − 6x2

alisha [4.7K]

-3x^2(6x^2 + 2x - 3) = -18x^4 - 6x^3 + 9x^2

8 0

3 years ago

Read 2 more answers

What is 1.625 rounded to the nearest hundreth?

makvit [3.9K]

1.625 rounded to the nearest hundreth is 1.63.

5 0

4 years ago

I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$