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lesantik [10]
3 years ago
11

Use the grouping method to factor x^3+x^2+2x+2

Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0

Factor out common terms in the first two terms, then in the last two terms

x^2(x + 1) + 2(x + 1)

Factor out the common term x + 1

<u>= (x + 1)(x^2 + 2)</u>

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Answer plzzzz. thanks
MakcuM [25]

Answer:   24

Step-by-step explanation:

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3 years ago
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Suppose you took two number cubes and pick a letter of the alphabet at random. Find the probability you roll 2 even numbers and
Fofino [41]
The answer will be 1/12
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(a) Select all that describe BD. B Perpendicular bisector of AC Angle bisector of LB Median of AABC Altitude of A ABC A None of
Fynjy0 [20]

a) Altitude of triangle ABC

b) Angle bisector of angle H

c) Median of triangle JKL

3 0
1 year ago
5x-10x+ 2(3y-2)= 10y-5x + 4
Bas_tet [7]
5x-10x+ 2(3y-2)= 10y-5x + 4

Multiply 2 x 3y and by -2

5x-10x+6y-4=10y-5x+4

You get 6y-4

-5x+6y-4=10y-5x+4

Subtract 10x from 5x to get -5x

6y-4=10y+4

Add 5x to the -5x

6y=10y+8

Add 4 to the other side to get 8

-4y=8

Subtract 6y-10y to get -4y

-4y/-4=8/-4

Divide -4y and 8 by -4 to get y by itself and -2

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Answer

Hope this helps
6 0
3 years ago
How can this same solution be written using set builder notation? {x | x &gt; }?
skad [1K]

<u>Corrected Question</u>

The solution to an inequality is represented by the number line. How can this same solution be written using set-builder notation? {x | x > }

Answer:

\{x | x >3 \}

Step-by-step explanation:

Given an inequality whose solution is represented by the number line attached below.

We observe the following from the number line

There is an open circle at 3, therefore the solution set does not include 3. (We make use of > or < in cases like that)

The arrow is pointed towards the right. All points to the right of 3 are greater than 3, therefore:

The solution in the number line can be written using set-builder notation as:

\{x | x >3 \}

5 0
4 years ago
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