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3 years ago

6) A climber is on a hike. After 2 hours she is at an altitude of 400 feet. After 6 hours, she is at an

Mathematics

1 answer:

Bas_tet [7]3 years ago

3 0

Answer:

<em>Her rate of change is 75 ft/h</em>

Step-by-step explanation:

<u>Rate of Change</u>

It measures how one quantity varies with respect to another. The second variable usually is the time.

The climber is hiking. We are given two points of her progress: At 2 hours, she is at 400 ft. This corresponds to the point (2,400).

At 6 hours, she is at 700 ft. This is the point (6,700)

The rate of change is the slope between these two points or the quotient of the variations of each variable:

$\displaystyle m=\frac{700\ ft-400\ ft}{6\ h-2\ h}$

$\displaystyle m=\frac{300\ ft}{4\ h}$

$m=75\ ft/h$

Her rate of change is 75 ft/h

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3 years ago

Element X is a radioactive isotope such that its mass decreases by 59% every day. If an experiment starts out with 390 grams of

miss Akunina [59]

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The function that represents the mass of the sample after t days is $A(t) = 390(0.41)^t$ .

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Step-by-step explanation:

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The exponential amount of decay for an amount of a substance after t days is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount, and r is the decay rate, as a decimal.

Element X is a radioactive isotope such that its mass decreases by 59% every day. The experiments starts out with 390 grams of Element X.

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The function that represents the mass of the sample after t days is $A(t) = 390(0.41)^t$ .

Hourly rate of change:

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3 years ago

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Answer:

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The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

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$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

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Therefore;

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