Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
The value of 18x + 9∆x - 7 based on the limit given will be 18x - 7.
<h3>How to calculate the value?</h3>
From the information given, it should be noted that we simply want to calculate the value of x.
This will be:
18x + 9∆x - 7
It was stated that ∆x = 0
Therefore, we'll put this into the equation.
This will be:
18x + 9∆x - 7
= 18x + 9(0) - 7
= 18x -7
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Answer:
your answer would be t=-1 or t=1
Step-by-step explanation:
-(2t-3) = 3t-2
Multiply
-2t+3 = 3t-2
Rearrange and Add up
-5t = -5
Divide both sides by 5
-t = -1
Multiply both sides by (-1)
t = 1
Which is the solution for the Negative Case
Solve the Positive Case
(2t-3) = 3t-2
Rearrange and Add up
-t = 1
Multiply both sides by (-1)
t = -1
have a great day!
