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3 years ago

Determine whether argument is valid 12. P-> p q ܆܇

Mathematics

1 answer:

Alik [6]3 years ago

4 0

Answer:

I think you meant $P\geq p*q$

It would false

Step-by-step explanation:

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How do you do 10? Give me explanation

forsale [732]

Answer:

1/10

Step-by-step explanation:

Percent spent on cable TV = 10%

Percent means "per hundred".

So, we can write 10% as,

10/100

= 1/10

So the family spent 1/10 of their total budget on cable TV.

7 0

3 years ago

Find the standard deviation and variance of the sample 93, 73, 76, 86, 98.

Novay_Z [31]

Total Numbers = 5
Mean (Average) = 85.2
Standard deviation = 10.70981
Variance(Standard deviation) = 114.7
Population Standard deviation = 9.57914
Variance(Population Standard deviation) = 91.76

5 0

3 years ago

Damon bought a girl he likes chocolate for valentines day. After tax they cost $13.60. If tax was 8.5%, what was the cost of the

Agata [3.3K]

Answer:

$12.53

Step-by-step explanation:

13.60 / 1.085 = 12.53

5 0

3 years ago

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Story Problems

Alex777 [14]

the answer is anna square hope this helps did this before

6 0

3 years ago

"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

Contact [7]

A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

$1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \ x\\5^2+10^2 \ \textgreater \ x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x^2 \ \textless \ 125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x \ \textless \ \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \ 10\\ 5^2+x^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}$

$3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \ 10\\ x^2+5^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}$

8 0

4 years ago

Read 2 more answers