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jek_recluse [69]
3 years ago
7

Matt thinks of a number. when he multiplies it by 5 and adds he gets the same as when he multiplies it by 6 and subtracts 5. wha

t is this mystery number?
Mathematics
1 answer:
krek1111 [17]3 years ago
3 0
The number is 10.
5*10=50
50+5=55
6*10=60
60-5=55
You might be interested in
Aaron has a triathlon. Sunday he bikes 12 5/8 miles and swims 5 2/3 miles. Monday, he runs 6 3/8 miles. How many total miles Aar
Alla [95]
Let’s put these into one fraction each:

Biking:
= (12*5)/8 miles
= 60/8 miles
This can be reduced to,
= 15/2 miles

Swimming:
= (5*2)/3 miles
= 10/3 miles

Running:
= (6*3)/8 miles
= 18/8 miles
This can be reduced to,
= 9/4

Now we add all the distances up:
= (15/2) + (10/3) + (9/4)

Now we just can add the numerators and the denominators. We must find the lowest common factor (LCF) for our 3 denominators (2,3,4). Our LCF turns out to be 12. *Remember what we do to the denominator we must do to the numerator. So:
= (15/2) + (10/3) + (9/4)
= [(15*6)/12] + [(10*4)/12] + [(9*3)/12]
= (90/12) + (40/12) + (27/12)
= (157/12)
Therefore Aaron Ran 157/12 miles or 13.08 miles.

Hope this helps!
4 0
3 years ago
The prime factorization of each number is given. List all the factors of each number in prime factorization form.
frutty [35]

Answer:

1,11,13,17,143,187,221,2431

Step-by-step explanation:


5 0
3 years ago
What is the answer to this math equation? - 1 5/8 + 9 1/4
SIZIF [17.4K]
I think -4 something
4 0
3 years ago
The value of 14 is 35% of
neonofarm [45]

Answer:

40

Step-by-step explanation:

(35/100) of X = 14

(7/20) × X = 14

X = 14 × 20/7

X = 40

4 0
3 years ago
Read 2 more answers
Two companies, A and B, make express delivery for small-item packages in a city. Company A charges a flat fee of RM70 per packag
bazaltina [42]

Using the <u>normal probability distribution and the central limit theorem</u>, it is found that:

a) There is a 0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

b) The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem:

  • When a <u>fixed constant k</u> multiplies a variable, the mean is k\mu and the standard deviation is k\sigma
  • When two normal variables are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question, b is needed to solve a, so I am going to place the solution to item b first.

Item b:

Flat fee of RM20(not considered for the standard deviation), plus a variable fee of RM3.5, hence:

\mu_B = 20 + 3.5(9) = 51.5

\sigma = 6.1(3.5) = 21.35

The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

Item a:

This probability is P(B - A) > 0. For the distribution, we have that:

\mu_{B-A} = \mu_B - \mu_A = 51.5 - 70 = -18.5

Since A has a constant fee, it's standard deviation is 0, hence:

\sigma_{B-A} = \sqrt{\sigma_A^2 + \sigma_B^2} = \sqrt{21.35^2} = 21.35

The probability is <u>1 subtracted by the p-value of Z when X = 0</u>, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 + 18.5}{21.35}

Z = 0.87

Z = 0.87 has a p-value of 0.8078.

1 - 0.8078 = 0.1922.

0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

A similar problem is given at brainly.com/question/25403659

3 0
2 years ago
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