<img src="https://tex.z-dn.net/?f=%20543_%7Bx%7D%20%3D%20%20244_%7Bx%7D%20%2B%20%20255_%7Bx%7D%20%5C%3A%20find%20%5C%3A%20the%20

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3 years ago

%5C%3A%20value%20%5C%3A%20of%20%5C%3A%20base%20%5C%3A%20x" id="TexFormula1" title=" 543_{x} = 244_{x} + 255_{x} \: find \: the \: value \: of \: base \: x" alt=" 543_{x} = 244_{x} + 255_{x} \: find \: the \: value \: of \: base \: x" align="absmiddle" class="latex-formula">
find the value of base x

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

Will u be my frndd........??

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Step-by-step explanation:

5-2+7x6-2

3+42-2

45-2

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3 years ago

X+103=180<br> Enter the measurement of the exterior angle of the triangle.

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Step-by-step explanation:

x + 103 = 180

x = 180 - 103

x = 77°

also by properties:

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Answer: $\bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}$

<u>Step-by-step explanation:</u>

$\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}$

$\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}$

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3 years ago

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sergij07 [2.7K]

When y=3/x translated right 3 units , we get y = 3/(x-3).
Then we translate y = 3/(x-3) , 3 units up and get y = 3/(x-3) +3.
So the answer is B.
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AnnZ [28]

Answer:

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