A^2-9a+20=a^2-5a-4a+20=(a^2-5a)+(-4a+20)
a^2-9a+20=a(a^2/a-5a/a)+(-4)(-4a/(-4)+20/(-4))
a^2-9a+20=a(a-5)-4(a-5)
a^2-9a+20=(a-5)[a(a-5)/(a-5)-4(a-5)/(a-5)]
a^2-9a+20=(a-5)(a-4)
I would say it’s B because out of ten it makes the mean 1 point higher
28. -1/3=r-3/4
Move -3/4 to the other side. Sign changes from -3/4 to +3/4
-1/3+ 3/4=r-3/4+3/4
-1/3+3/4=r
Find the common denominator for both of the fractions which is 12. Multiply by 4 for -1/3. Multiply by 3 for 3/4.
-1/3(4)+3/4(3)= -4/12+9/12= 5/12
33. -5/6+c=-11/12
c=-11/12+5/6
Find the common denominator which is 12 for 5/6. Multiply by 2. 5*2=10, 6*2=12
c=-11/12+10/12=-1/12
34. s-1/9=5/18
s-1/9+1/9=5/18+1/9
Find the common denominator which is 18. Mutiply by 2 for 1/9 . 1*2=2, 9*2=18
s=5/18+2/18=7/18
Answers:
28. 5/12
33. -1/12
34. 7/18
Answer:
<A = 75degrees
Step-by-step explanation:
From the triangle given;
arcDA + arc AD + arcBD = 360 degrees
131 + 79 + arcBD = 360
210 + arcBD = 360
arcBD = 360 -210
arcBD = 150 degrees
Since the angle at the vertex <A is half that at the arc BD, hence;
<A = 1/2 arcBD
<A = 1/2 * 150
<A = 75degrees
Hence the measure of angle A s 75degrees
