2 years ago

Find the Least Common Denominator of the fractions: 3/5 and 27

Mathematics

1 answer:

Flauer [41]2 years ago

3 0

Answer: 5

Step-by-step explanation:

The LCM for the denominators 5 and 1 is 5. So that means the LCD is 5.

3/5 = 3/5 x 1/1 = 3/5

27 = 27/1 x 5/5 = 135/5

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Evaluate a + b for a= 34 and b= -6

SpyIntel [72]

Answer:

Hey there!

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3 years ago

A solid exerts a force of 400 N. The pressure exerted by the solid on a surface, if area of contact is 2m2 will be

lubasha [3.4K]

Original equation : fg=mg

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2 years ago

A scientist had 3/4 of a bottle of a solution. She used 1/6 of the solution in an experiment. How much of the bottle did she use

enot [183]

To work this out you need to multiply 3/4 by 1/6.
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3 years ago

Read 2 more answers

Chloe has enough sand to fill a sandbox with an area of 36 square units. She wants the outer edges of the sandbox to use as litt

sergiy2304 [10]

Answer:

The dimensions of the box is 6 × 6 units.

Step-by-step explanation:

Chloe fill a sand box whose area is 36 square units.

Let length be x units and width be y units.

Area of box = 36

$xy=36\\y=\dfrac{36}{x}\ \ \ ...(i)$

Perimeter of box, $P=2(x+y)$

$P=2(x+\dfrac{36}{x})\ \ \ \ \ \ \ \ [\text{ From }(i)]$

Differentiate w.r to x

$\dfrac{dP}{dx}=2(1-\dfrac{36}{x^2})$

For critical point, $\dfrac{dP}{dx}=0$

$\therefore 2(1-\dfrac{36}{x^2})=0$

$\Rightarrow x=\pm6$

x can't be negative.

$\dfrac{d^2P}{dx^2}=\dfrac{144}{x^3}\\\dfrac{d^2P}{dx^2}|_{x=6}=\dfrac{144}{216}>0(\text{min})$

$P_{min}=24$ units

Hence, Length = 6 units and width = 6 units

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2 years ago

Can someone please please help :(

stiks02 [169]

Answer:

DANG bro im sorry i feel bad for uu

Step-by-step explanation:

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2 years ago