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Furkat [3]
3 years ago
14

Find the Least Common Denominator of the fractions: 3/5 and 27

Mathematics
1 answer:
Flauer [41]3 years ago
3 0

Answer: 5

Step-by-step explanation:

The LCM for the denominators 5 and 1 is 5. So that means the LCD is 5.

3/5 = 3/5 x 1/1 = 3/5

27 = 27/1 x 5/5 = 135/5

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3 years ago
Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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