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Paraphin [41]
3 years ago
15

A honey bee flaps its wings at 220 flaps per second, a bumblebee flaps its wings at 145 flaps per second, and a mosquito flats i

ts wings at 600 flaps per second. which insect wing pitch would be lowest to highest
Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0

Answer:

it would be

bumblebee

mosquito

honey bee

Step-by-step explanation:

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PLSS HELP ASAP I WILL GIFE H BRAINLIEAST
valina [46]

Answer:

6 ft^2

Step-by-step explanation:

A=1/2 Base Height

A=1/2(3)(4)

A=6 ft^2

3 0
2 years ago
Yolanda makes $11.25 per hour at her part-time job. During one week, she worked 12 2/5 hours and also earned some tips. Her fina
Delicious77 [7]

Answer:

She earned $20 in tips.

Step-by-step explanation:

First, you need to work out how much pay she'd get for 12 hours work:

12 x $11.25 = $135 for 12 hours work

Then, find out 2/5 of $11.25 to find out how much she would get for the 2/5 of an hour she worked:

2/5 of $11.25 = $4.50

Add both these sums together to get her total pay for hours worked:

$135 + $4.50 = $139.50

Subtract that sum from her total pay to find out how much money she earned in tips:

$159.50 - $139.50 = <u>$20</u>

7 0
3 years ago
Read 2 more answers
Consider the quadratic equation x^2=4x-5. How many solutions does the equation have
alexandr402 [8]
There is no solution

8 0
3 years ago
PLEASE HELP ASAP !!
wariber [46]

Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

  • radius = 9cm / 2 = 4.5cm
  • length = 15 cm

<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

  • radius = 12yd
  • height = 40 yd

<u>3. Substitute and compute:</u>

      Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

  • height: H = 18cm
  • side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

          \text{Area of the base}=B=(11cm)^2=121cm^2

b) <u>Volume of the pyramid</u>:

         Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3

4 0
3 years ago
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Solve for x.<br> 9(x + 1) = 25 + x<br> O x= 2<br> O x = 3<br> x=4<br> Ox=5
Arturiano [62]
9x+9=25+x
8x=16
X=2
Hdkpugv
3 0
3 years ago
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