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valentina_108 [34]
3 years ago
14

What are the solutions to the equation over the complex numbers?

Mathematics
2 answers:
STALIN [3.7K]3 years ago
7 0

Start with

x^2+75=0

Subtract 75 from both sides:

x^2=-75

Take the square root of both sides. As usual, this implies a double sign on the right hand side:

x=\pm\sqrt{-75}=\pm\sqrt{(-1)75}=\pm\sqrt{-1}\sqrt{75}=\pm\sqrt{75}i

So, the two answers are

\sqrt{75}i,\quad -\sqrt{75}i

Ede4ka [16]3 years ago
3 0

Answer:

  -5√3 i,   5√3 i.

Step-by-step explanation:

x^2 + 75 = 0

x^2 = -75

x = +/- √-75

= +/- √75 i

=  +/- 5√3 i.

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Answer:

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Find the solutions to the equation 102x + 11 = (x + 6)2 – 2. Which values are approximate solutions to the equation? Check all t
yKpoI14uk [10]

Answer:

x = 0.256286, 89.7437

Step-by-step explanation:

Step 1: Write equation

102x + 11 = (x + 6)² - 2

Step 2: Solve for <em>x</em>

  1. Expand: 102x + 11 = x² + 12x + 36 - 2
  2. Combine like terms: 102x + 11 = x² + 12x + 34
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  4. Subtract 102x on both sides: 0 = x² - 90x + 23
  5. Quadratic Formula: x=\frac{90 \pm \sqrt{(-90)^2-4(1)(23)} }{2(1)}
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