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valentina_108 [34]
3 years ago
14

What are the solutions to the equation over the complex numbers?

Mathematics
2 answers:
STALIN [3.7K]3 years ago
7 0

Start with

x^2+75=0

Subtract 75 from both sides:

x^2=-75

Take the square root of both sides. As usual, this implies a double sign on the right hand side:

x=\pm\sqrt{-75}=\pm\sqrt{(-1)75}=\pm\sqrt{-1}\sqrt{75}=\pm\sqrt{75}i

So, the two answers are

\sqrt{75}i,\quad -\sqrt{75}i

Ede4ka [16]3 years ago
3 0

Answer:

  -5√3 i,   5√3 i.

Step-by-step explanation:

x^2 + 75 = 0

x^2 = -75

x = +/- √-75

= +/- √75 i

=  +/- 5√3 i.

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Step-by-step explanation:

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Do the parenthesis first

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Step-by-step explanation:

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Answer:

a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

If

m > 0, then a line is rising

m < 0, then a line is falling

m = 0, then a line is horizontal

m is undefined, then a line is vertical

<h2>a.</h2>

(2, 1) and (4, 5)

m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}

<h2>b.</h2>

(-1, 0) and (3, -5)

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<h2>c.</h2>

(2, 1) and (-3, 1)

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<h2>d.</h2>

(-1, 2) and (-1, -5)

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