Tossing a regular coin 3 times, what is the probability of getting heads every time? 4)

2 answers:

6 0

The probability of getting heads on the first toss is 1/2 .

Then, the probability of getting heads on the second toss is 1/2 .

Then, the probability of getting heads on the third toss is 1/2 .

The probability of all three things happening is ...

(1/2) x (1/2) x (1/2) = 1/8 = 0.125 = 12.5% .

cluponka [151]3 years ago

6 0

1/2 times 1/2 times 1/2 would be 1/8. in percentage, 12.5%

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$dV=542.9 cm^{3}$

Step-by-step explanation:

Let's start with the equation of the volume of a cylinder:

$V=\pi r^{2}*h$

Where:

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We can us partial derivatives to find the differential of this volume. So we will have:

$dV=\frac{\partial V}{\partial r}dr+\frac{\partial V}{\partial h}dh$ (1)

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$\frac{\partial V}{\partial r}=2\pi r*h=2\pi 12*60=4523.9 cm^{2}$

$\frac{\partial V}{\partial h}=\pi 12^{2}=452.4 cm^{2}$

dr is a differential of the radius, so in our case it is 0.1 cm and dh, differential of the high, is 0.1*2 cm. We multiply by 2 because we need to consider the top and the bottom of the cylinder.

Now we just need to put all of this definitions in the equation (1).

$dV=4523.9*0.1+452.4*0.2=542.9 cm^{3}$