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Cloud [144]
3 years ago
9

−8/9⋅5/6 pls only correct answers. will give 30 points

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
6 0

Answer:

Exact Form: 20 /27

Ivan3 years ago
4 0

Answer:

- 20/27

Step-by-step explanation:

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Any altitude of an isosceles triangle is also a median of the triangle true or false ?
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The altitude drawn to the base is the median and the angle bisector.

Answer is true

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Simplify (−6.5)(−4)(−2.8)
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Find the domain and range of the function f(x)= 8|x|+sinx
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Explain why you think manufacturers frequently package their products in tall boxes, bottles, or cans
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Suppose that in a random sample of 300 employed Americans, there are 57 individuals who say that they would fire their boss if t
otez555 [7]

Answer:

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 300, \pi = \frac{57}{300} = 0.19

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 - 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.1456

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 + 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.2344

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

4 0
3 years ago
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