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Paul [167]
3 years ago
10

A doughnut shop charges $0.80 for each doughnut and $0.40 for a carryout box. How many doughnut can Mr. mac buy if he wants to s

pend at most $5.20 hint: crear an inequality equation and solve for "x". look for the key word and fing out which inequality symbol it is
Mathematics
2 answers:
Mandarinka [93]3 years ago
7 0
The answer would me 4.33 if you do it on a calculator
GenaCL600 [577]3 years ago
4 0
Cost for one doughnut=0.80+0.40=1.20
1.20x leq 1.20x \leq  5.20
x \leq 5.20/1.20
as x is an integer
so x=4



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The mean student loan debt for college graduates in Illinois is $30000 with a standard deviation of $9000. Suppose a random samp
Nataly [62]

Answer:

the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

Step-by-step explanation:

Given that:

Mean = 30000

Standard deviation = 9000

sample size = 100

The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:

P(31000 < X < 33000) = P( X \leq 33000) - P (X \leq 31000)

P(31000 < X < 33000) = P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P(Z \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{3000}{\dfrac{9000}{10}}}) -P(Z \leq \dfrac{1000}{\dfrac{9000}{10}}})

P(31000 < X < 33000) = P( Z \leq 3.33)-P(Z \leq 1.11})

From Z tables:

P(31000 < X

P(31000 < X

Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

8 0
3 years ago
Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10
AnnyKZ [126]

Answer:

a)P=0.42

b) n\geq 297

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}

a) we have k=2, n=10 and p=0.01:

P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42

b) We have, 1-(1-p)^n=P, Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297

4 0
3 years ago
Mary and Julie both have a goal of raising $1000 for charity. Mary raises $12 every 4 days. Julie raises $19 every 6 days.
baherus [9]
Julie would reach her goal first. Julie would reach her goal in approximately 316 days while it would take Mary approximately 333 days to reach it.

I know this because the steps to solve the problem are:

1.) 1,000/12 = 83.333 (to find how many days it would take her everyday)

2.) 83.333x4 = 333 (multiplying the answer by four makes it every four days)

3.) determine that it takes Mary 333 days

4.) 1,000/19 = 52.631 (just like step 1 but with different numbers)

5.) 52.631x6 = 316 (just like in step 2 but different numbers)

6.) determine it takes Julie 316 days

7.) 316 < 333 (takes Julie less time)
6 0
3 years ago
Read 2 more answers
This is important please help I will give brainiest​
hodyreva [135]
D. Bobby drew a diagram that’s not a function.

You can see by the arrows, function means domain cannot have two different ranges. Bobby made a mistake since it should’ve been a function
8 0
3 years ago
Are G and F mutually exclusive events? Explain. G and F are mutually exclusive because if you are not a finalist, then you canno
Alika [10]

Answer: G and F are mutually exclusive because they cannot occur together

Step-by-step explanation:

According to the definition of mutually exclusive events,

The events which can not occur together and probability of them occurring together is 0 are known as mutually exclusive events.

The first statement gives an implication that if one happens then other happens meaning they could both still happen so it is not true.

The second statement contradict the question about being mutually exclusive events.

The third statement also is a implication that if one event occurs then other does or does not occur.

The last statement is correct one that conforms with the question and obeys the definition of mutually exclusive events.

8 0
3 years ago
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