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alina1380 [7]
2 years ago
6

The coordinates of the community center are (5, −1). Who has a house in the same quadrant as the community center?

Mathematics
2 answers:
Debora [2.8K]2 years ago
7 0

Answer:

roy

Step-by-step explanation:

WINSTONCH [101]2 years ago
3 0
(5,-1) is located in quadrant IV......quadrant IV has (+ x, -y).....so any points that have (+ x, - y) are in this quadrant. 
Example : (6,-3) is in this quadrant......(2,-4) is also in this quadrant. 
So whoever has the house with (+ x, -y) is going to be in the same quadrant as the community center.
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Answer:

x=7, y=10. (7, 10).

Step-by-step explanation:

9x-5y=13

-4x+5y=22

-------------------

5x=35

x=35/5

x=7

9(7)-5y=13

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Answer:

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John and Tim are looking at the equation the square root of the quantity of 3 times x minus 4 equals square root of x . John say
IgorC [24]
The equation is 
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9x^2 - 24x + 16 = x
9x^2 - 24x + 16-x = x-x
9x^2 - 25x + 16 = 0

Now use the quadratic formula. See the attached image for those steps.

After using the quadratic formula the two possible solutions are x = 1 or x = 16/9

We need to check each possible solution to see if it is extraneous or not.

----------------------------

Checking x = 1

3x - 4 = sqrt(x)
3*1 - 4 = sqrt(1)
3 - 4 = 1
-1 = 1

The final equation is false, so x = 1 is not a true solution

x = 1 is extraneous. 

So far, John is correct; however, we need to see the nature of the possible solution x = 16/9

So let's check it
----------------------------

Checking x = 16/9

3x - 4 = sqrt(x)
3*(16/9) - 4 = sqrt(16/9)
48/9 - 4 = 4/3
16/3 - 4 = 4/3
16/3 - 12/3 = 4/3
(16 - 12)/3 = 4/3
4/3 = 4/3

The last equation is true, so x = 16/9 is a proper solution.

This solution is considered non-extraneous. So Tim is also correct
----------------------------

They are both correct because there are two possible solutions. One of which is extraneous (x = 1) and the other is non-extraneous (the fraction x = 16/9)

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