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4 years ago

Write an equation in point-slope form. Crossing the x-axis at x = -3 and the y-axis at y = 6

Mathematics

1 answer:

Travka [436]4 years ago

8 0

Answer:

y = 2x + 6

Step-by-step explanation:

The equation for a linear line is y = mx + c.

We know we want it to cross the y-axis at 6, so the y-intercept (c) can be assumed to be 6.

If we substitute in the x that we want, we end up with this:

0 = m(-3) + 6

m = 2

So now we can form the equation:

y = 2x + 6

You might be interested in

A positive integer is 11 more than 18 times another. Their product is 6030. Find the two integers.

allsm [11]

Answer:

18 and 335

Step-by-step explanation:

y = 18x + 11

x * y = 6030

x * (18x + 11) = 6030

18x^2 + 11x = 6030

18x^2 + 11x - 6030 = 0

(18x + 335)(x - 18) = 0

18x + 335 = 0 x - 18 = 0

18x = -335 x = 18

x = -335/18

x is gonna have to be a positive number...so x = 18

y = 18x + 11

y = 18(18) + 11

y = 324 + 11

y = 335

so ur numbers are 18 and 335

4 0

4 years ago

Read 2 more answers

63 plus what gives you 83

iVinArrow [24]

83-63=20
So your answer is 20

5 0

3 years ago

Find the surface area of a cylinder with a diameter of 8<br> yards and a height of 9 yards.

marysya [2.9K]

Answer:

a=326.76 yd^2

Step-by-step explanation:

a= 2pi(d/2)h+2pi(d/2)^2=2pi(8/2)9+2pi(8/2)^2= 326.72564yd^2

5 0

3 years ago

What are the roots of the polynomial equation x3 - 6x = 3x2 - 8? Use a graphing calculator and a system of equations.

makkiz [27]

Answer:

d : 4, 1, -2.

Step-by-step explanation:

There's no need for a calculator in my opinion because we can use the rational root theorem which states that the equations of this form:

$\sum_{i=0}^{n} a_{i}x^i = 0 = a_{0} + a_{1}x + a_2x^2 + ... + a_nx^n = 0\\ a_i \in \mathbb{Z}$

Have rational roots, than the roots are of the form: $\frac{k \cdot a_o}{p \cdot a_n}, \ where \ k, p \in \mathbb{Z}.$

Rewriting the equation we have:

$x^3 - 3x^2 -6x + 8 = 0\\By \ our\ previous \ claim \ x \in D_8 \ where \ D_n \ the \ set \ of \ divisors \ of \ n.\\D_8 = \{\pm 1, \pm 2, \pm 4, \pm 8\} \\We \ plug \ in \ some \ number from \ D_8.\\Letting \ x = -2;\\(-2)^3 -3(-2)^2 -6(-2) + 8 = 0 \ \ \ Thus \ x+2 \ is \ a \ factor.\\We \ can \ now \ simplify \ the \ eq. \ using \ Polynomial \ Long \ Division.$

$x^3 -3x^2 -6x + 8 = (x+2)(Q(x))\\To \ find \ Q \ we \ divide \ the \ original \ equation \ by \ x + 2; which \ yields:\\Q(x) = x^2 - 5x + 4.\\So \ we \ can \ use \ the \ quadratic \ formula \ to \ find \ the \ roots:\\x = 4,x = 1. \\Thus \ x \in \{-2, 1, 4\}. \ \ These \ are \ all \ the \ roots.$

5 0

4 years ago

Clause: if 0>1 then 0>0

Bezzdna [24]

Step-by-step explanation:

false

0 can't he greater then any integer.

4 0

3 years ago

Write an equation in point-slope form. Crossing the x-axis at x = -3 and the y-axis at y = 6​

Write an equation in point-slope form. Crossing the x-axis at x = -3 and the y-axis at y = 6