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Artemon [7]
4 years ago
5

Is 12, 15, and 9 an right angel

Mathematics
1 answer:
Vesna [10]4 years ago
8 0

if it was a right angle it would follow the rule for A^2+B^2=C^2

9^2+12^2=15^2

81+144=225

225=225

yes it is a right angle.

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Please help me with the question below (also please explain).
devlian [24]

To find the surface area of the given figure identify all the faces on the figure, calculate the area of each face and then sum the areas:

Measures in red

Number of faces in green, total faces 9

Area of a triangle:

A=\frac{1}{2}bh

Area of a rectangle:

A=bh

Area of faces 1 and 2(rectangles):

\begin{gathered} A_1=A_2=20in*11in \\ A_1=A_2=220in^2 \end{gathered}

Area of faces 3 and 4 (triangles):

\begin{gathered} A_3=A_4=\frac{1}{2}(12in)(9in) \\  \\ A_3=A_4=54in^2 \end{gathered}

Area of faces 5 and 6 (rectangles):

\begin{gathered} A_5=A_6=12in*5in \\ A_5=A_6=60in^2 \end{gathered}

Area of faces 7 and 8 (rectangles):

\begin{gathered} A_7=A_8=20in*5in \\ A_7=A_8=100in^2 \end{gathered}

Are of face 9 (rectangle):

\begin{gathered} A_9=20in*12in \\ A_9=240in^2 \end{gathered}

Total surface area:

\begin{gathered} SA=A_1+A_2+A_3+A_4+A_5+A_6+A_7+A_8+A_9 \\  \\ SA=220in^2+220in^2+54in^2+54in^2+60in^2+60in^2+100in^2+100in^2+240in^2 \\  \\ SA=1108in^2 \end{gathered}<h2>Then, the surface area of the given figure is 1108 square inches</h2>

4 0
1 year ago
Use the drop-down menus below to state the sequence of transformations that maps Figure D onto Figure E in the animation below.
Masja [62]

Answer:

Reflection, Translation

Congruent, reflections, and translations

Step-by-step explanation:

You reflect it diagonally and translate it by 3 units down.

Reflecting diagonally gives you the grayed-out shape, and translating it 3 units down will give you Figure E.

The shape is the same because no changes in size were used.

-Chetan K

7 0
2 years ago
What is the function rule represented by the following table?
Romashka-Z-Leto [24]

Answer:

y=-4x+3

Step-by-step explanation:

as x=0

put in y= -4x+3

y= -4(0)+3

y=3

now put x=1 in y= -4x+3

y= -4(1)+3

y= -1

now put x=2 in y= -4x+3

y= -4(2)+3

y=-5

3 0
3 years ago
Smallest number that has 2,5,7 as its prime numbers?
devlian [24]

Answer:

70

Hope this helps

4 0
3 years ago
Reasoning triangle $abc$ has a perimeter of $12$ units. the vertices of the triangle are $a(x,\ 2),\ b(2,-2)$ , and $c(-1,\ 2)$
OlgaM077 [116]

hmmm let's find the distance between B and C first off.

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{-2})\qquad C(\stackrel{x_2}{-1}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{(~~-1 - 2~~)^2 + (~~2 - (-2)~~)^2} \implies BC=\sqrt{(-1 -2)^2 + (2 +2)^2} \\\\\\ BC=\sqrt{( -3 )^2 + ( 4 )^2} \implies BC=\sqrt{ 9 + 16 } \implies BC=\sqrt{ 25 }\implies BC=5

hmmm if BC is that much, then AB + AC = 7, since AB + AC + BC = 12 which is the perimeter, Check the picture below.

6 0
2 years ago
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