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3 years ago

Graph the image of QRS after a rotation 270º counterclockwise around the origin.

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

8 0

Answer:

Q=(1,-5)

R=(5,-5)

S=(2,-7)

Step-by-step explanation:

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Pls help!!! Question in the picture

Wewaii [24]

Answer:

-7, - $\pi$ - $\sqrt{3}$ , 9

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Y = 5x + 15 y = -5x - 15

algol [13]

Answer:

5x + 15 = -5x - 15

10x = -30

x = -3

y = 5(-3) + 15 = -15 + 15 = 0

(-3,0)

Step-by-step explanation:

3 0

3 years ago

Verify that -tan2x = (2tanx) / (sec^2x - 2)

sashaice [31]

Answer:

Below.

Step-by-step explanation:

- tan 2x = -2tanx / (1 - tan^2x)

Using the identity tan^2x = sec^2x - 1 and substituting for tan^2x:

- tan 2x = -2 tanx / (1 - (sec^2x - 1))

= 2 tanx / ( - 1(sec^2x + 2))

= 2 tan x / (sec^2 x - 2)

8 0

3 years ago

Hamburgers are sold in packages of 20, while buns are sold in packages of 12. What are the least numbers of packages you should

aleksley [76]

Answer:

3 packages of hamburger and 5 packages of bun.

Step-by-step explanation:

3x20=60

5x12=60

5 0

2 years ago

Read 2 more answers

F(x)=2x^3+ax^2-37x-60 The binomial x-4 is a factor of f(x). Find the value of a.

jekas [21]

Given:

The function is

$f(x)=2x^3+ax^2-37x-60$

The binomial $x-4$ is a factor of f(x).

To find:

The value of $a$ .

Solution:

If $x-c$ is a factor of f(x), then $f(c)=0$ .

It is given that, $x-4$ is a factor of f(x), then $f(4)=0$ .

We have,

$f(x)=2x^3+ax^2-37x-60$

Substituting x=4, we get

$f(4)=2(4)^3+a(4)^2-37(4)-60$

$f(4)=2(64)+a(16)-148-60$

$f(4)=128+16a-208$

$f(4)=16a-80$

Now,

$f(4)=0$

$16a-80=0$

$16a=80$

$a=\dfrac{80}{16}$

$a=5$

Therefore, the value of a is 5.

6 0

2 years ago