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2 years ago

The outdoor temperature is 4 degrees below 0, or

Mathematics

1 answer:

sleet_krkn [62]2 years ago

3 0

Hi Chloe!

Answer:

The outdoor temperature is -4 degrees.

The indoor temperature is 72 degrees.

Explanation:

We use negative integer to represent loss, below , or withdrawal etc. On the other hand we use positive integers to show gain , above , deposit etc.

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Y = 8x + 10<br><br> y = 2<br><br> whats the substitution ?

viva [34]

Answer:

Look at the explanation.

I'll be online so let me know if you still need help.

Step-by-step explanation.

A system of equations is basically two or more equations that rely on each other. If a solution for a variable is 2, it has to work for the other equation.

The substitution is basically plugging in the y value to y = 8x + 10

If y = 2

and also y = 8x + 10

What do you think the substitution is?

3 0

2 years ago

♥||Please help A.S.A.P i will mark you brainliest!||♥

photoshop1234 [79]

Answer:

90°-43°=47°

Step-by-step explanation:

complementary is two angles added up to 90 degrees

I hope this helps :)

3 0

2 years ago

Help me please please

Alecsey [184]

Answer:

it is 50

Step-by-step explanation:

50 is the answer becasue i got a 10 on the test

6 0

2 years ago

Read 2 more answers

Which of these needs the denominator rationalized? -PLEASE HELP

valentinak56 [21]

Answer:

option b

Step-by-step explanation:

$\sqrt{ \frac{5}{3} }$

$\frac{ \sqrt{5} }{ \sqrt{3} }$

the denominator is in the surd form, so it must be rationalized

4 0

3 years ago

1.) What is the equation of the path of firework #1? Write your equation in general form.

valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in $y=ax^2+bx+c$

it's easier to find vertex form first then expand to get general form

vertex form is $y=a(x-h)^2+k$ where the vertex is (h,k) and a is a constant

firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

$h_1=a(t-10)^2+50$

to find the value of $a$ , subsitute another point

(0,0)

$0=a(0-10)^2+50)$

$0=100a+50$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_1=\frac{-1}{2}(t-10)^2+50$

expand to get general form

$h_1=\frac{-1}{2}(t^2-20t+100)+50$

$h_1=\frac{-1}{2}t^2+10t-50+50$

$h_1=\frac{-1}{2}t^2+10t$

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is $h_2=a(t-10)^2+72$

find $a$

use another point

(0,22)

$22=a(0-10)^2+72$

$22=100a+72$

$-50=100a$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_2=\frac{-1}{2}(t-10)^2+72$

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50

domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0

2 years ago