Question:
A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.
Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling a number greater than 2.
If there is more than one element in the set, separate them with commas.
Answer:
Step-by-step explanation:
Given
A roll of a 6 sided number cube
Solving (a): The sample space
This implies that we list out all number on the number cube.
So:
Solving (b): Outcomes greater than 2
This implies that we list out all number on the number cube greater than 2 i.e. 3 to 6.
So:
The system r+l = 46 and 15r + 9l = 396 can be used to determine the number of raspberries boxes and lemon seed boxes sold.
Step-by-step explanation:
Given,
Cost per box of raspberry = $15
Cost per box of lemon seeds = $9
Total boxes sold = 46
Total revenue generated = $396
Let,
r represent the number of raspberries sold
l represent the number of lemon seeds sold
According to given statement;
r+l = 46 Eqn 1
15r + 9l = 396 Eqn 2
The system r+l = 46 and 15r + 9l = 396 can be used to determine the number of raspberries boxes and lemon seed boxes sold.
Answer:
Step-by-step explanation:
Be VERY careful. When it write out the equation that way, it will give the speculation of this:
Now, in this case, since you were extra explanatory about this [what is written in parentheses], two factors I know of that multiply to 15 are these:
** 
I am joyous to assist you at any time. ☺️
1) 6÷0.2 = 30
If 6/2=3 then 6/0.2=30 as the decimal place shifts one place.
2)8÷0.1 = 80
8/1=8 so shift the decimal place over once to make 80.
3)9÷0.3 = 30
9/3=3 so shift the decimal place over once to get 30.
4)4÷0.04 = 100
4/4=1 so shift the decimal place over twice to get 100.
5)7÷0.002 = 3500
7/2=3.5 so shift the decimal place over three times to get 3500
6)0.718÷0.2 = 3.59
718/2=359 so shift the decimal over three places for the 0.718 and then back over once for the 0.2
7)0.0141÷0.003 = 4.7
141/3=47 so shift the decimal over our times for the 0.0141 and then back over three times for the 0.003
8)0.24÷0.012 = 20
24/12=2 so shift the decimal point over once twice for 0.24 then back over three times for 0.012
9)1.625÷0.0013 = 1250
1625/13=125 so shift the decimal point over three times for the 1.625 and then back four times for the 0.0013
10)47.1÷0.15 = 314
471/15=31.4 so shift the decimal point over once for the 47.1 and then back over twice for the 0.15.
Hope this helps :)
Answer:
1. c
2. b
3. a
4. d
5. e
6. f
Step-by-step explanation:
