1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
laila [671]
3 years ago
15

Will someone help me?

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
I know they already answered decreasing but Its decreasing I did not look at the answer I promise but whatever XD 
myrzilka [38]3 years ago
5 0
Hey there! 

The answer would be Decreasing because the slope of the line is a negative number. As you can see, the numbers on the points of the line are getting smaller and smaller. Smaller numbers = decreasing.
You might be interested in
Triangle MPT with NR || MT is shown below the dimensons are in centimeters which measurements is closest to the length of RT in
svlad2 [7]

Step-by-step explanation:

do u have like a photo or sum to explain it better

7 0
2 years ago
8. The expression (x+5)(x+8)+(x+5)(2x - 3) can be written as the product of (x + 5) and
ale4655 [162]

Answer:

(x + 5)(3x + 5)

Step-by-step explanation:

(x - 5)(x + 8) + (x + 5)(2x - 3) ← factor out (x + 5) from each term

= (x + 5)(x + 8 + 2x - 3)

= (x + 5)(3x + 5)

8 0
2 years ago
Will marke as bianleast <br> Find the LCM of 6 and 10.<br><br> 2<br><br> 30<br><br> 20<br><br> 60
nataly862011 [7]

Answer: 30 is the least common multiple of 6 and 10.

Step-by-step explanation:

30/6= 5

30/10= 3.

4 0
3 years ago
Read 2 more answers
Zaheer, a boy of height 1.5m was watching the entire programme. Initially he observed the top of the flag pole at an angle of el
7nadin3 [17]

Answer:

15.2 m

Step-by-step explanation:

You need to draw a figure. Start by drawing a horizontal segment approximately 10 cm long; that is the ground. Label the left end point A and the right endpoint B. On the right endpoint, B, go up a short 1 cm vertically. That is 1.5 m, the height of Zaheer. Label that point C. Now from that point draw a horizontal line that ends up above point A. Label that point D. Now go back to point C. Draw a segment up to the left at a 30 deg angle with CD. End the segment vertically above point D. Label that point E. That is the top of the flagpole. Draw a vertical segment down from point E through point D ending at point A. Segment AE is the flagpole. Go back to point C. Move 3 cm to the left on segment CD, and draw a point there and label it F. That is where Zaheer moved to. Now connect point F to point E. That is a 45-deg elevation to point E, the top of the flagpole.

m<EFD = 45 deg

m<EFC = 135 deg

m<FEC = 15 deg

m<ECD = 30 deg

We now use the law of sines to find EC

(sin 15)/10 = (sin 135)/EC

EC = 27.32

Because of the 30-60-90 triangle, ED = EC/2

ED = 13.66

Now we add the height of Zaheer to find AE.

13.66 + 1.5 = 15.16

Answer: 15.2 m

7 0
3 years ago
6x-4=2x+8 What do i do here​
Charra [1.4K]

Answer:

x = 3

Step-by-step explanation:

6x - 4 = 2x + 8

6x - 2x = 8 + 4

4x = 12

x = 12/4

x = 3

4 0
3 years ago
Read 2 more answers
Other questions:
  • Owen solves the equation below and his steps are shown. When he plugged his solution back into the original equation, he did not
    8·1 answer
  • Which of the following is a feature of a credit card?
    8·1 answer
  • Which of these triangles appear not to be congruent to any others shown here ? Check all that apply.
    12·2 answers
  • PLLLLLLLEEEEEEEEEEEEEEASE ANSWER FAST MATH GENIUSES!!!!!!!
    14·2 answers
  • The box is 3/4 inch long 1/2 inch wide and 1/4 inch deep what is the volume of the box
    10·1 answer
  • Find the sum 9/10 + 4/100 =?
    10·1 answer
  • if y=12x+7 were changed to y=12x+2, how would the graph of the new function compare with its original
    6·1 answer
  • Solve the exponential equation-<br><br> (-5)^2x=625
    5·2 answers
  • -11 + 2r = 5r - 6 - 5
    15·2 answers
  • I NEED HELP WITH MATH
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!