Answer:
15
Step-by-step explanation:
To find the answer, plug the values of each variable into the equation and simplify. It may be easiest to plug one variable in at a time, simplify, then plug the next variable in. Remember, if the equation is asking you to subtract a negative number, the negatives cancel and you want to add the numbers.
b = 2 c = -4
3b - c + 5 <----- Original expression
3(2) - c + 5 <----- Plug 2 in for "b"
6 - c + 5 <----- Multiply 3 and 2
11 - c <----- Add 6 and 5
11 - (-4) <----- Plug -4 in for "c"
15 <----- Add 11 and 4
You should add -77 to 77 because it will cancel out.
Complete Question
Consider the isosceles triangle. left side (2z+8)units, bottom of triangle (4z-10)units, right side of triangle (2z+8) units Part A Which expression represents the perimeter of the triangle? a.(4z+16) units b.(6z−2)units c.(8z−16) units d.(8z+6) units
Answer:
d. (8z + 6) units
Step-by-step explanation:
The formula for the Perimeter of a Triangle is :Side A + Side B + Side C
Hence,
(2z + 8)units + (4z - 10) units + (2z + 8)units
= (2z + 8 + 4z - 10 + 2z + 8)units
Collect like terms
= 2z + 4z + 2z + 8 - 10 + 8
= 8z + 6 units
The expression that represents the perimeter of the triangle is (8z +6) units
Answer:
r = i + j + (-2/3)(3i - j)
Step-by-step explanation:
Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant
if a = i + j ; b = t(3i - j) and r = -i +s(j)
for this to be true all the vector components must be equal
summing i 's
i + 3ti = -i; then t = -2/3
j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3
so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j
Answer:
1170450 yd^2
Step-by-step explanation:
The first thing is to calculate the necessary perimeter, which would be like this:
2 * a + b = 3060
if we solve for b, we are left with:
b = 3060-2 * a
Now for the area it would be:
A = a * b = a * (3060-2 * a
)
A = 3060 * a -2 * a ^ 2
To maximize the area, we calculate the derivative with respect to "a":
dA / da = d [3060 * a -2 * a ^ 2
]/gives
dA / day = 3060 - 4 * a
If we equal 0:
0 = 3060 - 4 * a
4 * a = 3060
a = 3060/4
a = 765 and d
Therefore b:
b = 3060 - 2 * a = 3060 - 1530 = 1530
A = a * b
A = 765 * 1530
A = 1170450 and d ^ 2
