For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that 
is such that
Obviously, both limits are 0, so 
is indeed continuous at 
.
Now, for to be differentiable everywhere, its derivative 
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:
and at this time, we don't know what's going on at , so we omit that case. We want to be continuous, so we require that
from which it follows that 
.
Answer:
I'm notttt sureeeeee I think its C i don't know,
C) Undefined
formula: y-y/x-x
9--5= 9+5=14
-5--5= -5+5= 0
14/0
you can't divide by 0 so it's undefined
An equality of two rations is called a porportion
He will need exactly 24 stickers. To get this number, you must multiply both sides. :)
