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saul85 [17]
3 years ago
12

(5.02) The area of the parallelogram below is ___ square meters.

Mathematics
2 answers:
Anarel [89]3 years ago
8 0
A= Bh
A = 9(7) = 63 m^2
Afina-wow [57]3 years ago
4 0

Answer:

multiply 2 times 7 then 9 times 2 then 9 times 7. add them up and you will get your answer

Step-by-step explanation:

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Make r the subject of the formula t=r/r-3
trapecia [35]

Answer:

r = t(r-3)

Step-by-step explanation:

t = r/r-3

r/r-3 = t

r = t x (r-3)

6 0
3 years ago
Is the product of fifteen negative integers positive or negative?
enot [183]

Answer:

the sign of the product of 15 negative numbers will be negative

Step-by-step explanation:

Heya mate!!

The product of odd numbers is odd and the product of even numbers is even.

so 15 is an odd number then the sign of product is odd

Hope this helps!!!

3 0
3 years ago
Does anyone wanna be friends lol?
USPshnik [31]

Answer:

hahaha me

Step-by-step explanation:

...actually how old are you though lol

7 0
3 years ago
Read 2 more answers
Can someone please help my with my work.
Aleksandr [31]

Answer:

X+0.375=y

Step-by-step explanation:

6 0
3 years ago
pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base
kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

We expect your answer is supposed to be Step 4.

7 0
3 years ago
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