Consider the number 4n , where n is a natural number. Check whether there is any value of e N for which 4n ends with the digit z
1 answer:
You might be interested in
Well, I'm way past the 15 min mark, but here's how to do the question.
With this, you will need to use the distance formula, , on XY, YZ, and ZX.
XY:
Firstly, solve inside the parentheses:
Next, solve the exponents:
Next, solve the addition, and XY's distance will be √29
(The process is the same with the other 2 sides, so I'll go through them real quickly)
YZ:
ZX:
Now that we got the 3 sides, we can add them up:
In short, your answer is 14.8, or the second option.