3 years ago

Please I really need help with this question!!

Mathematics

1 answer:

IRINA_888 [86]3 years ago

8 0

1.92559524e-44 would be the answer i think

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Plis i need help whit this questionss

zmey [24]

Question 1: x+2 = 8 doesn't belong in the given equations.

Question 2: The possible values for y are 0,1 and 2

Step-by-step explanation:

Question: Which one doesn't belong?

We will solve each equation one by one to get which equation doesn't belong with others

So,

$x+4 = -2\\x+4-4 = -2-4\\x = -6$

$x+5 = -1\\x+5-5 = -1-5\\x = -6$

$x+2 = 8\\x+2-2 = 8-2\\x = 6$

$3-x=9\\3-x-3 = 9-3\\-x = 6\\x = -6$

Hence,

x+2 = 8 doesn't belong in the given equations.

Question 2:

Given equation is:

$x+y = 5$

It is given that the values of x will be greater than 2 and less than 6 so values of x can be 3,4 and 5

So,

$3+y = 5\\y = 5-3\\y = 2\\\\4+y = 5\\y = 5-4\\y = 1\\\\5+y = 5\\y = 5-5\\y = 0$

Hence,

The possible values for y are 0,1 and 2

So,

x+2 = 8 doesn't belong in the given equations.

The possible values for y are 0,1 and 2

Keywords: Linear equation, variables

Learn more about linear equations at:

#LearnwithBrainly

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EXTRA POINTS PLEASE HELP I'LL GIVE BRAINLIEST

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Opposite sides are equal.

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