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Marina86 [1]
3 years ago
11

Solve for the variable b. 5a(b - c ) = d

Mathematics
2 answers:
Liula [17]3 years ago
3 0
5a(b-c)=d. Here, we are trying to isolate the variable b.
Divide both sides by 5a: b-c=d/(5a)
Add c to both sides: b= \frac{d}{5a} +c
Naddik [55]3 years ago
3 0
Your answer is attached below, along with the steps. Have a good night :)

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How many people choose football or soccer than baseball or basketball.
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Step-by-step explanation:

8 football, 6 baseball and basketball, 5 soccer

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the rectangular gable is 8 feet tall the area of the gable is 120 square feet, what is the length of the base
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15 js the base of the rectangle because you find the area by doing length times width
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(6+8)^2=6^2+8^2 statement true
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3 years ago
The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi
Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

P(X=x)=(_{x}^{n})\ p^xq^{n-x}

P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009

P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097

P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043

P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117  

P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0
3 years ago
Read 2 more answers
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horsena [70]
The distance between the Earth's surface and the upper edge of the Earth's atmosphere would be Q - V.

The distance from the Sun to the Earth is Q. The distance from the Sun to the upper edge of the atmosphere is V. If you subtract V from Q, the remaining distance is that of the Earth's atmosphere.  Q - V = the atmosphere
6 0
3 years ago
Read 2 more answers
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