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xz_007 [3.2K]
3 years ago
6

Mary can type six letters in 20 minutes, Maggie can type five letters in 20 minutes, and Su Ying can type two letters in 20 minu

tes. Working together, and assuming that each letter is of the same length, how many minutes will it take them to type 45 letters?
Mathematics
1 answer:
marin [14]3 years ago
8 0

Answer:

70 minutes

Step-by-step explanation:

Mary can type the number of letters in 20 minutes = 6

Maggie can type the number of letters in 20 minutes = 5

Su Ying can type the number of letters in 20 minutes = 2

Working together they can type the number of letters in 20 minutes

= 6 + 5 + 2

= 13 letters

Working together they can type the number of letters in 1 minute = \frac{13}{20}

To type 45 letters time taken by them = \frac{45}{\frac{13}{20} }

                                                               = 45\times \frac{20}{13}

                                                               = \frac{900}{13}

                                                               = 69.230 ≈ 70 minutes

It will take them 70 minutes to type 45 letters.

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top fin: 3x2.25/2=3.375, 3x0.75/2=1.125, 3.375+1.125=4.5

bottom fin: 1x1/2= 0.5, 1x0.5/2=0.25, 0.5+0.25=0.75

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between tail and body: 2.5x2=5

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total area of khianna's fish is 75.75 cm.

hope this helps

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Step-by-step explanation:

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\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

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