Answer:
a) 8 pounds.
b) [26,42]
c) 
d) Weight above 42 pounds, so she cannot.
Step-by-step explanation:
a. What is the margin of error?
Within 8 pounds, so margin of error of 8 pounds.
b. Express the acceptable weights as an interval.
34 - 8 = 26
34 + 8 = 42
[26,42]
c. Write an expression in the format to represent the interval.

d. Sally weighs 44 pounds. Can she play in the bounce house?
Weight above 42 pounds, so she cannot.
Answer:
The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Step-by-step explanation:
Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.
The random variable <em>X</em> is exponentially distributed with mean 7 minutes.
Then the parameter of the distribution is,
.
The probability density function of <em>X</em> is:

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

![=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148](https://tex.z-dn.net/?f=%3D%5Cint%5Climits%5E%7B9%7D_%7B6%7D%20%7B%5Cfrac%7B1%7D%7B7%7D%5Ccdot%20e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B7%7D%5Ccdot%20%5Cint%5Climits%5E%7B9%7D_%7B6%7D%20%7Be%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5B-e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%5D%5E%7B9%7D_%7B6%7D%5C%5C%5C%5C%3De%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%206%7D-e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%209%7D%5C%5C%5C%5C%3D0.424373-0.276453%5C%5C%5C%5C%3D0.14792%5C%5C%5C%5C%5Capprox%200.148)
Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Answer:
cans extra food is needed to feed the second cat.
Step-by-step explanation:
Given:
When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve a total of 11/2 cans each day.
Now, to find the extra food is needed to feed the second cat.
Food needed for one cat = 
Food needed for both one and second cat needed = 
Now, extra food needed to feed the second cat:
<u><em>Food needed for both one and second cat needed - food needed for one cat.</em></u>
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Therefore,
extra food is needed to feed the second cat.
Answer: Width of canvas = 9 inches
Area left for painting after painting the border = 70 square inches.
Explanation :
Since we have given that
Area of painting = 108 square inches
Length of canvas = 12 inches
As we know that


So, breadth of canvas = 9 inches .
Now, Chloe paints a 1 inch wide blue border on the canvas.


Hence, remaining area = 70 square inches .