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Amanda [17]
3 years ago
11

When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve

a total of 11/2 cans each day. How much extra food is needed to feed the second cat
Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

5\frac{3}{10}  cans extra food is needed to feed the second cat.

Step-by-step explanation:

Given:

When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve a total of 11/2 cans each day.

Now, to find the extra food is needed to feed the second cat.

Food needed for one cat = \frac{1}{5}\ of\ can.

Food needed for both one and second cat needed = \frac{11}{2}\ =5\frac{1}{2}\ cans.

Now, extra food needed to feed the second cat:

<u><em>Food needed for both one and second cat needed - food needed for one cat.</em></u>

<u><em /></u>\frac{11}{2} -\frac{1}{5}\\\\=\frac{55-2}{10} \\\\=\frac{53}{10}<u><em /></u>

<u><em /></u>=5\frac{3}{10}\ cans.<u><em /></u>

Therefore, 5\frac{3}{10}\ cans extra food is needed to feed the second cat.

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What is the length of the diagonal for the given rectangular prism to the nearest whole unit? A) 10 cm B) 11 cm 6 cm D) 13 cm
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\large\boxed{\text{B. 11 cm.}}

Begin by using Pythagorean theorem to solve for the length of the diagonal of the base:

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