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3 years ago

SARAH SAYS THE VALUE OF 13^0 is o. Moriah says the value is 1. who is correct and why? show your proof

Mathematics

1 answer:

vodka [1.7K]3 years ago

5 0

Moriah is correct because any number to the power of 0 will always be 1.

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What is the recursive formula for this geometric sequence? –4, –24, –144, –864, ...

lesya [120]

the question does not present the options, but this does not interfere with the resolution

Let

a1=-4

a2=-24

a3=-144

a4=-864

a5=?

we know that

a2/a1=-24/-4----> 6-------> a2=6*a1

a3/a2=-144/-24---> 6-----> a3=6*a2

a4/a3=-864/-144---> 6----> a4=6*a3

therefore

a5=6*a4-----> a5=6*(-864)------> a5=-5184

hence

the formula is

an=6*a(n-1)

<span>n and (n-1) are subscripts </span>

3 0

3 years ago

Enter the fraction 33100 as a decimal

Mariulka [41]

Answer:

0.33

Step-by-step explanation:

If you have the number 1 and divide it by 100, you get 1/100, 0.01, or 1% of 1. If you multiply 1/100 by 33, you get 33/100, 0.33, or 33% of 1.

7 0

3 years ago

Read 2 more answers

The high temperature for one town last year was 79°F The low temperature for the same town was - 3°F What was the difference bet

Ainat [17]

Answer:

79°c - (-3°c) = 82°c

Step-by-step explanation:

this is because we need to calculate the total gap between those numbers through number line. I have attached the photo, have a look over there.

6 0

3 years ago

Does the table show a direct proportional relationship? If so, what is the constant of proportionality?

lesantik [10]

Answer:

C. Yes, 3.5.

Step-by-step explanation:

If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality ( $k$ ) is described by the following expression:

$k = \frac{y}{x}$ (1)

Where:

$x$ - Input.

$y$ - Output.

If we know that $(x_{1}, y_{1}) = (13, 45.5)$ , $(x_{2}, y_{2}) = (14, 49)$ and $(x_{3}, y_{3}) = (15, 52.5)$ , then the constants of proportionalities of each ordered pair are, respectively: