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Studentka2010 [4]
3 years ago
13

What is 2792 + 9383790202

Mathematics
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

9383792994

Step-by-step explanation:

I the answer is 9383792994

Y_Kistochka [10]3 years ago
5 0
938,381,812 around there I did this with my head and I’m not sure if it’s correct but I hope it is
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A rectangle has a perimeter of 84 meters. One dimension is 7 meters. How long is
Lemur [1.5K]

Answer:

The unknown dimension is 35

Step-by-step explanation:

The perimeter of a rectangle is l+l+w+w or 2l+2w (l=length, w=width)

l+l+w+w=84

7+7+w+w=84

14+w+w=84

then we subtract 14 from 84

w+w=70

2w=70

\frac{70}{2}=35

w=35

Let's check our answer

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3 years ago
Find the distance between each pair of points. round your answer to the nearest tenth, if necessary. (-8, -5), (-4, 3)
Anuta_ua [19.1K]
The answer would be 8.9
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3 years ago
Solve by completing the square x^2-6x-4=0
Vesna [10]

Answer:

x = 3 ± \sqrt{13}

Step-by-step explanation:

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = 4 + 9

(x - 3)² = 13 ( take square root of both sides )

x - 3 = ± \sqrt{13} ( add 3 to both sides )

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6 0
2 years ago
A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm
MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x\geq25.8  upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

<em>F(x,a,b)= </em>\frac{1}{b-a}<em>   </em>a\leq x\leq b

            =1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)=\frac{x-a}{b-a} =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

7 0
3 years ago
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