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3 years ago

Solve the equation x^4-10x^2+24=0

1 answer:

8 0

I hope this helps you

x^4-10x^2+24=0

x^2 -6

x^2 -4

(x^2-6)(x^2-4)=0

x^2-6=0 x^2=6 x=square root of 6

x^2-4=0 x^2=4 x=-2 or x=2

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Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sisters birthday party. what is the largest number o

Vinil7 [7]

The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Given that Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sister's birthday party and asked to find out the largest numbers of snacks in the bag.

There are 24 jolly ranchers and 56 blow pops and For the maximum numbers of snacks in the bag can be 24 jolly ranchers and 56 blow pops.

The maximum numbers of snacks that can be filled in a snacks bag is 24 jolly ranchers and 56 blow pops.

Therefore,The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Learn more about numbers here:

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7 0

1 year ago

A medical researcher needs 6 people to test

nadezda [96]

$\boldsymbol{\mathbf{Answer}}$

$\boldsymbol{\mathbf{1235520\,different\, ways\,can\,six\, people\,be\, selected}}$

$\boldsymbol{\mathbf{Step-by-step explanation}}$

A medical researcher need to select 6 people out of 13 people who have volunteered for the test in

To find, how many ways can 6 people be selected.

= ${13}\times{12}\times{11}\times{10}\times{9}\times{8}$

$\boldsymbol{\mathbf{= 604800 ways}}$

$\boldsymbol{\mathbf{1235520\,different\, ways\,can\,six\, people\,be\, selected}}$

4 0

3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

Simplify.<br> Х+4/3x^2+7x - 20

pickupchik [31]

Answer:4/3x²+8x−20

Step-by-step explanation:Combine Like Terms:

=x+

x2+7x+−20

x2)+(x+7x)+(−20)

x2+8x+−20

8 0

3 years ago

Geometry- what is O? show work/explain please.

adelina 88 [10]

Answer:

Step-by-step explanation:

5 0

3 years ago