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never [62]
4 years ago
7

How does changing the function from f(x) = −5 cos 2x to g(x) = −5 cos 2x − 3 affect the range of the function?

Mathematics
2 answers:
Alla [95]4 years ago
6 0
The graph has been moved 3 units downward, making the range change. The range of f(x) is [-5,5], while the range of g(x) is [-8,2]. The picture is of both functions. f(x) is blue, g(x) is red.

inna [77]4 years ago
5 0

Answer:

[-8,2]

Step-by-step explanation:

We are given that the function f(x) is transformed to the function g(x), where,

f(x) =-5 \cos 2x and g(x) =-5 \cos 2x-3.

Since, the range of \cos x is [-1,1].

<em>Thus, the range of a\cos bx is {-a,a].</em>

So, the range of f(x) =-5 \cos 2x is [-5,5].

As, we are translating the function f(x) 3 units downward to get g(x).

<em>The graph of the function is shifted 3 units down.</em>

So, the range of g(x) will be [-5-3,5-3] = [-8,2].

Hence, the range of g(x) =-5 \cos 2x-3 is [-8,2].

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A vertical lamppost of height 6 m is at P When Sam stands at the point A. the shadow formed is 2.1 m long. When Sam stands at th
Damm [24]

Step-by-step explanation:

triangle ADA' and OPA' are similar so, using property of similar triangles :

6/AD = (13.3+3.6-PB'+2.1)/2.1

{A'P = 13.3 +3.6 - PB' + 2.1}

6/AD = (16.9-PB'+2.1)/2.1

6/AD = (19-PB')/2.1 - EQN I

As we know, AD = BC as both of them are Sam's height (constant)

triangle OPB' and BCB' are similar so, using property of similar triangles:

6/BC = PB'/3.6

OR, 6/AD = PB'/3.6 (AD = BC) - EQN II

Now,

comparing EQN I AND II we get :

(19-PB')/2.1 = PB'/3.6

or, 68.4 - 3.6PB' = 2.1PB'

or, 68.4 = 5.7PB'

so, PB' = 12 m

Now, as we know,

6/BC = PB'/3.6

OR, 6/BC = 12/3.6

OR, (6×3.6)/12 = BC

<h3>so, BC = 1.8 m</h3><h3>so, BC = 1.8 mso, AD = 1.8 m</h3>

So, the height of Sam is 1.8 m.

tanA' = AD/AA'

<A' = tan‐¹(1.8/2.1)

<B' = tan‐¹(1.8/3.6)

Now,

<A'OB' = 180 - tan‐¹(1.8/2.1) - tan‐¹(1.8/3.6)

<A'OB' = 112.833

<h3>so, <A'OB' = 113° (approx.)</h3>

7 0
2 years ago
A rocket is divided into three sections: the payload and navigation section in the top, the fuel section in the middle, and the
Zarrin [17]

Answer:

Let's name each of the three sections of the rocket as:

-P payload and navigation

-F fuel

-E engine

Now, we are told that:

The top section is one-sixth the length of the bottom section:

P=\frac{1}{6}E    (1)

The middle section is one-half the length of the bottom section:

F=\frac{1}{2}E   (2)

The total length is 240ft:

P+F+E=240ft    (3)

We may begin by substiting (1) and (2) in equation (3), in order to find the value of the engine section E:

\frac{1}{6}E+\frac{1}{2}E+E=240ft    

E=144ft    (4)>>>> Value of the engine section length

Then, we substitute this value of E in equations (1) and (2):

P=\frac{1}{6}144ft  

P=24ft   (5)>>>> Value of the payload and navigation section length

F=\frac{1}{2}144ft  

F=72ft    (6)>>>> Value of the fuel section length

5 0
3 years ago
Does (9, 0) make the equation y = 8x + 9 true?
marissa [1.9K]

nope. bc...

0 ≠ 72 + 9.

yw!

5 0
3 years ago
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Vlada [557]
That would be d -73
7 0
3 years ago
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mezya [45]

Answer:

27, 15, 13

Step-by-step explanation:

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