Answer:
BC = 18.34°
Step-by-step explanation:
Recall: Exterior angle formed by 2 secants = ½(the difference of the measures of the intercepts arcs)
Thus:
m<BAC = ½(DE - BC)
27.42° = ½(73.18 - BC) => Substitution
Multiply both sides by 2
2*27.42 = 73.18 - BC
54.84 = 73.18 - BC
BC = 73.18 - 54.84
BC = 18.34°
9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
You can make an equation with these numbers.
182 ÷ 2 = 91 ÷ 2 = 45.5
Hope this helps!
Well, I think what u could do is put 1 where the decimal is and 0 by however many numbers there are, for example, 1.13/ 100. There is a 1 for the decimal and two 0 for the two numbers. And then simplify as much as you can and then make it into a mixed fraction if you have to like if it is 9/5 or something
Answer:
x = -3
y = 7
Step-by-step explanation:
x + 3y = 18
-3x - 12y = -75
multiply first equation by 4
4 × (x + 3y) = 18 ➡ 4x + 12y = 72
now add the two equations up
4x + 12y - 3x -12y = 72 - 75 (-12y will eliminate 12y)
x = -3
