QUESTION 1a.
We want to add
![( - 2 {x}^{2} - 4x + 13) + (12 {x}^{2} + 2x - 25)](https://tex.z-dn.net/?f=%28%20-%202%20%7Bx%7D%5E%7B2%7D%20%20-%204x%20%2B%2013%29%20%2B%20%2812%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20-%2025%29)
We group similar terms to get
![- 2 {x}^{2} + 12 {x}^{2}- 4x + 2x - 25 + 13](https://tex.z-dn.net/?f=-%202%20%7Bx%7D%5E%7B2%7D%20%20%2B%2012%20%7Bx%7D%5E%7B2%7D-%204x%20%2B%202x%20%20%20-%2025%20%2B%2013)
Simplify:
![- 10{x}^{2} - 2x -12](https://tex.z-dn.net/?f=-%2010%7Bx%7D%5E%7B2%7D%20-%202x%20%20-12)
QUESTION 1b.
The given function is:
![(7x^2+4x-26)-(-7x^2-3x+15)](https://tex.z-dn.net/?f=%287x%5E2%2B4x-26%29-%28-7x%5E2-3x%2B15%29)
Expand the parenthesis to obtain,
![7x^2+4x-26 + 7x^2 + 3x - 15](https://tex.z-dn.net/?f=7x%5E2%2B4x-26%20%2B%207x%5E2%20%2B%203x%20-%2015)
Group similar terms,
![7x^2+7 {x}^{2} + 4x + 3x-26 - 15](https://tex.z-dn.net/?f=7x%5E2%2B7%20%7Bx%7D%5E%7B2%7D%20%20%2B%204x%20%2B%203x-26%20%20-%2015)
Simplify:
![14{x}^{2} + 7x-41](https://tex.z-dn.net/?f=14%7Bx%7D%5E%7B2%7D%20%20%2B%207x-41)
QUESTION 2
The given function is
![f(n)=n^2-6n-16](https://tex.z-dn.net/?f=f%28n%29%3Dn%5E2-6n-16)
The zeros of this function is given by;
![n^2-6n-16 = 0](https://tex.z-dn.net/?f=n%5E2-6n-16%20%3D%200)
Split the middle term.
![n^2-8n + 2n-16 = 0](https://tex.z-dn.net/?f=n%5E2-8n%20%2B%202n-16%20%3D%200)
Factor;
![n(n - 8) + 2(n - 8) = 0](https://tex.z-dn.net/?f=n%28n%20-%208%29%20%2B%202%28n%20-%208%29%20%3D%200)
![(n - 8)(n + 2) = 0](https://tex.z-dn.net/?f=%28n%20-%208%29%28n%20%2B%202%29%20%3D%200)
![n - 8 = 0 \: or \: n + 2 = 0](https://tex.z-dn.net/?f=n%20-%208%20%3D%200%20%5C%3A%20or%20%5C%3A%20n%20%2B%202%20%3D%200)
![n = 8 \: or \: n = - 2](https://tex.z-dn.net/?f=n%20%20%3D%208%20%5C%3A%20or%20%5C%3A%20n%20%3D%20%20-%202)
A. 18m+45=t
m=months
t=total cost
b.
1 month=$63
6 months = $153
12 months (1 year)= $261
Expanded- 100000000+10000000+9000000+4
An 18% increase. I just used my handy dandy calculator.
Answer:
ok so umm i dont get what ur looking for?
Step-by-step explanation: