I am looking at ur first answer choice.....but something is off..
2^-4 = 1/(2^4) = 1/(2*2*2*2) = 1/16...this is correct
but ur answer choice says 2^-4 = 1/(2^-4)...and its supposed to equal 1/(2^4).
But I still think ur answer choice is A
Hello!
To solve this, first write two equations. We are given two facts about the situation, so we can write the equations accordingly.
Say the length of the rectangle is l, and the width is w.
<u>The length of a rectangle is 9 inches more than twice its width:</u> 2w + 9 = l, as you're adding 9 to two times the width.
<u>The perimeter of the rectangle is 48 inches:</u> The equation for perimeter is 2l + 2w, so we can just use that in this case to make the equation - 2l + 2w = 48
Now, set up the system of equations.

Now, we can already use substitution to solve. We get from one of the equations that l = 2w + 9, so we can substitute 2w + 9 for l in the other equation, and then solve for w.
2l + 2w = 48
2 (2w + 9) + 2w = 48
4w + 18 + 2w = 48
6w = 30
w = 5
We know one of our variables now. Now, all that's left to do is substitute 5 for w in one of the original equations to solve for l.
2w + 9 = l
2 (5) + 9 = l
10 + 9 = l
19 = l
Therefore, we now have our dimensions. The length of the rectangle is 19 inches, and the width is 5.
Hope this helps!
Answer:
E=2.8 m-40
Step-by-step explanation:
We konw that 30°E=25°M and 310°E=125°M
so if we want to write an ecuation that linearly relates E with M, we can use the formula of the line that crosses two points:
Y-y1= (y2-y1)/(x2-x1)*(X-x1)
In thts case:
- y1= E1= 30
- y2= E2=310
- x1= M1= 25
- x2=M2=125
so
E-E1= (E2-E1)/(M2-M1)* (M-M1)
E-30 = (310-30)/(125-25)*(M-25)
E-30 =280/100 *(M-25)
E-30 =2.8 M- 280*25/100
E-30 =2.8 M-70
E= 2.8 M-70+30
E=2.8 M-40
Good luck!
Answer:
y-8=(7)/(5)*(x+10)
Step-by-step explanation:
Answer:
it's 13a+2 pal!
Step-by-step explanation: