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belka [17]
3 years ago
8

The day before the day before yesterday was two days after the day before my birthday.

Mathematics
2 answers:
natta225 [31]3 years ago
4 0
The birthday would have been on saturday
nikdorinn [45]3 years ago
3 0

Answer:

Your answer is indeed Saturday.

Step-by-step explanation:

The day before, (Wednesday) the day before, (Tuesday) yesterday, (Monday).

And then after the day <em>before </em>my Birthday, (sunday and then Saturday.)

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Smith and his friends are gaming online on a popular website. An hour later, 6 friends go
Firlakuza [10]

Answer:

12

Step-by-step explanation:

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3 years ago
15 points+ brainliest! please help
nadya68 [22]

Answer: move right 4, move up 4

Step-by-step explanation:

8 0
3 years ago
Can someone please help me​
4vir4ik [10]

Answer:

40

Step-by-step explanation:

Two ways we can solve this problem:

1. Graphically

2. Mathematically

Because you already solved it graphically, I will show you how to do so mathematically. Of course, graphically is much much easier and more efficient in this problem.

Let's break the problem down.

First, we are given a graph which contains a slope.

To find slope, we use the technique -> rise/run

Picking 2 obvious points from the graph, we can see

1st point -> (10, 20)

2nd point -> (40, 80)

Now, let's find the slope

\frac{80-20}{40-10}  = \frac{60}{30}  = 2

Now, we have an equation y = 2x, where y = number of pies and x = cups of sugar

We want to find how many cups of sugar we need to bake 80 pies. Simply substitute 80 = number of pies = y

y = 2x -> 80 = 2x

Solving for x, divide both sides by 2

40 = x

We need 40 cups of sugar.

3 0
2 years ago
14×12 distributive property​
miss Akunina [59]
186 if that’s the answer you where looking for if not comment here it will give me a notification and I will see
5 0
3 years ago
You can mow one acre in 126 minutes. i can mow one acre in 117 minutes. how long will it take you to mow a 0.17-acre lawn? 13 in
Morgarella [4.7K]

a) (0.17 ac)×(126 min/ac) = 21.42 min

b) I can mow 1/126 ac/min; you can mow 1/117 ac/min. Together, we can mow at a rate that is the sum of these:

... (1/126 + 1/117) ac/min = (117 + 126)/(126×117) = 243/14,742 ac/min

Then it will take 14,742/243 min/ac × 0.17 ac/lawn ≈ 10.31 min/lawn

5 0
3 years ago
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