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Radda [10]
3 years ago
10

3m+4=1 with steps. THX

Mathematics
1 answer:
Fed [463]3 years ago
4 0
3m+4=1
subtract 4 on both sides
3m=-3
divide both sides by 3
m=-1

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Which set of side lengths forms a right triangle?
pochemuha

Awnser:

9,12,18

Step-by-step explanation:

you have to add the smallest numbers together and it has to be greater that the greatest number.

9+12= 21

21>18

4 0
3 years ago
Evaluate the following f(-2)+f(-3)=
8090 [49]
It would be =-5f
Hope this helps
7 0
3 years ago
300 juniors at Central High School took the ACT last year. The scores were distributed normally with a mean of 24 and a standard
Usimov [2.4K]

Answer:

150 students

Step-by-step explanation:

According to statement we have the following information

number of juniors=n=300

mean score=24

standard deviation score=4

The number of students that score above 24 is determined by

Number of students score above 24=number of juniors* P(student score above 24)

P(student score above 24)=P(x>24)=P(x-mean/sd>24-24/4)=P(z>0)=0.5.

Students score above 24=np=300*0.5=150

Hence there are 150 students scored above 24.

4 0
3 years ago
A customer is late paying their renewal registration fee. The renewal registration fee is $142.16 and the late fee is 63% of the
Andre45 [30]
$124.56 because if you have 63% you change it to a decimal so it is not .63 and you multiply it by 146.16 and then add the 35 you get 124.56
8 0
3 years ago
1. Exercise 18, section 5.4. Compute 90, 91, 92, 93, 94 and 95. Make a conjecture about the units digit of 9n where n is a posit
Burka [1]

Answer:

n is a positive integer and here 90, 91, 92, 93, 94 and 95 is 9⁰ = 1

9¹ = 9

9² = 81

9³ = 729

9⁴ = 6561

9⁵ = 59049

so mathematical induction is prove given below.

Step-by-step explanation:

9⁰ = 1

9¹ = 9

9² = 81

9³ = 729

9⁴ = 6561

9⁵ = 59049

lets us consider by P (n) for the base case n = 0 then 9⁰ = 1  So P (1) is true

k ≥ 1so consider all integers

1≤l≤ k

There is a need to prove P (k+1)

if k is odd

9^k^+^1 =9^k.9.

9^k is 9 so

9^k = 9 +10m

then

9^k^+^1 = 9 ( 9 + 10m)

       =81 + 10 (9m)

so digit is 1 and k +1 is even

3 0
3 years ago
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